A hollow closed cube of side 10 cm, each weighing 200 gm, is made. This cube is placed in water with a horizontal face. How many cm
of its height sinks in water if the density of water is 1 gm per cubic cm?
Answers
Step-by-step explanation:
volume × density = weight.
so, ( 10×10× height) × 1gm/cube cm. = 200
height= 2cm.
Given : A hollow cube of side 10cm each weighing 200gm, is made
This cube is placed in water with horizontal face
To Find : How many cm of its height sinks in water if density of water is 1gm/cm^3
Solution:
Weight of cube = Weight of Water displaced
Weight of cube = 200 g
Let sat cube sinks for d cm
Surface area of face = 10 * 10 = 100 cm²
=> Volume of water displaced = 100 * d cm³
density of water is 1gm/cm³
Density = weight / Volume
=> Weight of water displaced = 100d * 1 = 100d g
Equate both weights
=> 100d = 200
=> d = 2 cm
Hence 2cm of cube height sinks in water
Learn More:
The weight of body is found to reduce by 30%when immersed in ...
brainly.in/question/11126948
The relative density _____. A) has unit of kg/m³ B) has unit of g/m³ C ...
brainly.in/question/11755561