Math, asked by manjotjii13, 1 month ago

A hollow closed cube of side 10 cm, each weighing 200 gm, is made. This cube is placed in water with a horizontal face. How many cm
of its height sinks in water if the density of water is 1 gm per cubic cm?

Answers

Answered by shashanksinghal1929
2

Step-by-step explanation:

volume × density = weight.

so, ( 10×10× height) × 1gm/cube cm. = 200

height= 2cm.

Attachments:
Answered by amitnrw
1

Given : A hollow cube of side 10cm each weighing 200gm, is made

This cube is placed in water with horizontal face

To Find : How many cm of its height sinks in water if density of water is 1gm/cm^3

Solution:

Weight of cube =  Weight of Water displaced

Weight of cube =  200 g

Let sat cube sinks for d cm

Surface area of face = 10 * 10  = 100 cm²

=> Volume of water displaced = 100 * d  cm³

density of water is 1gm/cm³

Density = weight / Volume

=> Weight of water displaced = 100d  * 1  = 100d  g

Equate both weights

=> 100d = 200

=> d = 2 cm

Hence 2cm of cube height sinks in water

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