Question

A hollow conducting sphere has inner radius 5 cm
and outer radius 8 cm then find maximum possible
potential of conductor if breakdown electric field
of air is 3 x 106 V/m
(1) 240 kV
(2) 480 kV
(3) 960 kV
(4) 720 kV
1​

Answer 1

Dear Student,

● Answer - (1)

V = 240 kV

◆ Explanation -

# Given -

E = 3×10^6 V/m

r0 = 8 cm = 8/100 m

# Solution -

For a hollow sphere, electric field inside the sphere is zero.

Potential outside the sphere is given as -

V = E.r0

V = 3x10^6 × 8/100

V = 24 × 10^4

V = 240 × 1000

V = 240 kV

Hence, maximum possible potential of conductor is 240 kV.

Thanks dear. Hope this helps you..