A hollow cube of internal edge 22 cm is filled with spherical marbles of diameter 0.5 cm and it is assumed that 1/8 space of the cube remains unfilled. Find the number of marbles that the cube can accommodate.
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Answered by
3
Answer:
REF.Image
Spheriacl marble ∘
d=0.5cm
r=
2
0.5
cm
Space unfilled=
8
1
×v. of cube
space filled= (1−
8
1
)× volume of cube
=
8
7
× volume of cube
∴ space filled = no. of marbles × volume of each marbles.
8
7
×a
3
=N×
3
4
πr
3
8
7
×22×22×22=N×
3
4
×
7
22
×
2
0.5
×
2
0.5
×
2
0.5
N=49×484×6
=142296
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Answer:
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