Question

A hollow cylinder iron pipe is 35 cm. its outer and inner diameter is 10 cm and 8cm. find the weight of the pipe

Answer 1

h=35cm
r1=10/2 = 5cm
r2=8/2 = 4cm

volume of pipe = pi*h*(r1+r2)(r1-r2)
                     =22/7*35*(5+4)(5-4)
                     =990cm cube
therefore volume of cube is 990cm cube.

Answer 2

Disclaimer:

The weight of 1 cm³ of the metal is 7 gm.

Concept:

The volume of the hollow cylinder can be determined by subtracting the volume of the inner cylinder from the volume of the outer cylinder.

Given:

The length of the pipe, h = 35 cm

The inner diameter of the pipe, r = 8 cm

The outer diameter of the pipe, R = 10 cm

Find:

Weight of the pipe.

Solution:

The volume of the hollow cylinder can be calculated as,

V = πR²h - πr²h

V = πh (R² - r²)

V = (22/7)×35×((10/2)²- (8/2)²)

V = (22)×5×((5)²- (4)²)

V =  (22)×5×(25- 16)

V =  (22)×5×(9)

V = 990 cm³

Weight of 1 cm³ of the metal = 7 gm/cm³

m = 990 × 7 gm

m = 6930 gm

m = 6.93 kg

Hence, the weight of the pipe is 6.93 kg.

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