Question

a hollow cylinder is made of iron height 1m.Its inner diameter is 54 cm and thickness of iron sheet of cylinder is 9 cm .Find the weight of the hollow cylinder if 1 c.c of iron weighs 8 gm.

Answer 1

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Given : width of road roller = 1 m =100 cm
inner diameter = 54 cm
inner radius (r1)= 54/2 =27 cm
thickness = 9 cm
outer radius (r2) = 27+9 = 36 cm
volume of road roller (iron)= π*r^2*h= π*(r2-r1)*h=π*
(36^2-27^2)*100=22/7*567*100=178038
weight of 1 cm^3 = 8 gms
weight of 178038 cm^3 = 8*178038= 1424304gms= 1424.304 kg.