Question

.
A hollow cylinder of length 32 cm, external diameter
20 cm and thickness 4 mm is to be made. What
length of a solid right circular cylinder of diameter 4
cm is required to recast this hollow cylinder?​

Answer 1

Answer:

62.72 cm

Step-by-step explanation:

R = 10 cm

l = 32 cm

r = R - thickness

r = 10 - 0.4 = 9.6

Volume of Hollow cylinder = pie ( R^2 - r^2 ) * h

pie * 2^2 * h                         =  pie ( 10^2 - 9.6^2 ) * 32

h                                            =  0.4 * 19.6 * 8

h                                            = 62.72 cm

Answer 2

Answer:

Here, inner radius 10 cm-4 mm

N

10 cm=

48 5 cm

Volume of the hollow cylinder ={π * 10²*32– π(48/5)²*32}

32π 100-48x48= 25 {2500-2304}

32 = (196)

25

= 250.88% cm³

..Volume of solid right circular cylinder = r²h

According to the question,

th=250.88

π (2)² = 250.88 л

250.88

h=250.88/4

h = 62.72 cm