Question

A hollow cylinder of mass m and radius R is in pure rolling on a fixed horizontal surface with ​

Answer 1

Answer:

B) mv^{2}

Explanation:

Since the cylinder is performing pure rolling

$\omega r = v$

Rotational KE = $\frac{1}{2}I\omega^{2}$

where I = Moment of inertia = $mR^{2}$ for hollow cylinder

Rotational KE =

$\frac{1}{2}mR^{2}w^{2}\\\\\frac{1}{2}mR^{2}\frac{v^{2}}{R^{2}}\\\\\frac{1}{2}mv^{2}$

Transational KE = $\frac{1}{2}mv^{2}$

Total KE = $mv^{2}$

Might help THANKS!