A hollow cylinder of uniform density of mass 50 kg is placed on rough horizontal surface as shown
A horizontal pull F = 200 N is exerted to cylinder due to which acceleration of its topmost point P and angular
acceleration comes out to be a and a respectively. Choose the correct options. (Assume pure rolling)
यामान के एकसमान घनत्व के एक खोखले बेलन को दर्शाए अनसार खरदरी क्षैतिज सतह पर रखा जाता है।
Answers
Answered by
0
Answer:
F=ma
200=50*a
a=200/50
a=4m/s^2
Explanation: hope it helps u!!
Answered by
0
A hollow cylinder of uniform density of mass 50 kg
A horizontal pull F = 200 N is exerted to cylinder
- Given,
- m = 50 kg
- F = 200 N
- we have formula,
- F = ma
- ⇒ 200 = 50 × a
- ⇒ a = 200/50
- ∴ a = 4 m/s^2
Similar questions