Physics, asked by harshdeshwal20, 11 months ago

A hollow cylinder of uniform density of mass 50 kg is placed on rough horizontal surface as shown
A horizontal pull F = 200 N is exerted to cylinder due to which acceleration of its topmost point P and angular
acceleration comes out to be a and a respectively. Choose the correct options. (Assume pure rolling)
यामान के एकसमान घनत्व के एक खोखले बेलन को दर्शाए अनसार खरदरी क्षैतिज सतह पर रखा जाता है।​

Answers

Answered by paaru1610
0

Answer:

F=ma

200=50*a

a=200/50

a=4m/s^2

Explanation: hope it helps u!!

Answered by AditiHegde
0

A hollow cylinder of uniform density of mass 50 kg

A horizontal pull F = 200 N is exerted to cylinder

  • Given,
  • m = 50 kg
  • F = 200 N
  • we have formula,
  • F = ma
  • ⇒ 200  = 50 × a
  • ⇒ a = 200/50
  • a = 4 m/s^2
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