A hollow cylindrical iron pipe with external and internal radii 8cm and 6cm respectively and length 35cm is melted and recast into a solid wire of thikness 2.8cm .find the length of the wire.
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Answer:
515.78 cm.
Step-by-step explanation:
Volume of cylinder = π( R² - r² ) h
➡ Volume of cylinder =22 / 7 × ( 8² - 6² )× 35
➡Volume of cylinder =22 / 7 × ( 64 - 36 )× 35
➡ Volume of cylinder = 22 / 7 × 28 × 35
➡ Volume of cylinder = 22 × 5 × 28
➡ Volume of cylinder = 110 × 28
➡ Volume of cylinder = 3080 cm³
Volume of cylinder = Volume of wire = 3080 cm³
Therefore, Volume of wire = πr²l
3080 = 22 / 7 × 1.9 × l
➡ ( 3080 × 7 ) / ( 22 × 1.9 ) = l
➡ l = 515.78 cm
The length of the wire is 515.78 cm.
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