a hollow cylindrical pipe has inner circumference 44dm and outer 45dm. Find the cost of painting it from both sides (inside as well as outside) at ₹2 per meter square if length is 3.5m
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Answered by
33
inner circumference = 44dm = 4.4m
outer circumference = 45dm = 4.5 m
length = 3.5m
inner CSA = 4.4×3.5 = 15.4 m²
outer CSA = 4.5×3.5 = 15.75 m²
total = 15.4 + 15.75 = 31.15 m²
cost = Rs. 2 per m²
total cost = 31.15×2 = Rs. 62.30
outer circumference = 45dm = 4.5 m
length = 3.5m
inner CSA = 4.4×3.5 = 15.4 m²
outer CSA = 4.5×3.5 = 15.75 m²
total = 15.4 + 15.75 = 31.15 m²
cost = Rs. 2 per m²
total cost = 31.15×2 = Rs. 62.30
Answered by
1
Area To Be Painted = 2*pie*r*h+2*pie*R*h = h(2*pie*r+2*pie*R)
2*pie*r = 44 dm = 4.4 m
2*pie*R = 45 dm = 4.5 m
=>3.5(4.4+4.5)
=> 31.5 m2
Cost = 31.5*2 = Rs 63
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