a hollow cylindrical pipe is 21 cm long. Its inner and outer diameters are 6cm and 10 cm ,respectively.Find the volume of the metal used in making the pipe.
Answers
Answered by
40
volume of cylinder = π(R²-r²)*h
= π(5²-3²)*21
= π(25-9)*21
= π(16)*21
= 22÷7×16×21
= 1056 cm³
= π(5²-3²)*21
= π(25-9)*21
= π(16)*21
= 22÷7×16×21
= 1056 cm³
Answered by
23
The volume of the used metal 1056 cm³
Given data :
Outer diameter = 10 cm
Inner diameter = 6 cm
Height = 21 cm
So,the outer radius = 10/2 = 5 cm
Inner radius = 6/2 = 3 cm
So, hollow space volume = π ×(3)²×21 = 22/7×9×21 = 594 cm³
So, total volume = π × (5)² × 21 = 22/7 × 25 × 21 = 1650 cm³
Metal volume = (1650-594) = 1056 cm³
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