Question

A hollow cylindrical pipe is 21 m. long its inner and outer diameters are 6 cm. and 10 cm. respectivly find the volume of the metal used in make the pipe

Answer 1

hi friend
here's your answer looking for
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here ,
h= 21m or 210cm

so,
inner volume =
$\pi {r}^{2} h \\ = \frac{22}{7} \times 3 \times 3 \times 210 \\ = 22 \times 270 \\ = 5940 {cm}^{3}$
outer volume =
$\pi {r}^{2} h \\ = \frac{22}{7} \times 5 \times 5 \times 210 \\ = 22 \times 750 \\ = 16500 {cm}^{3}$
volume of metal used=
$(16500 - 5940) {cm}^{3} \\ = 10560 {cm}^{3}$
☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣☣
for your more help I had also attached the image
from brainly benefactor
Amaytripathi19

Answer 2

Find the volume with diameter = 6 cm

Radius = Diameter ÷ 2

Radius = 6 ÷ 2 = 3 cm

Volume = πr²h

Volume = π(3)²(21) = 594 cm³

Find the volume with diameter = 10 cm

Radius = Diameter ÷ 2

Radius = 10 ÷ 2 = 5 cm

Volume = πr²h

Volume = π(5)²(21) = 1650 cm³

Find the volume of the metal used:

Volume = 1650 - 594 = 1056 cm³

Answer: The volume of the metal used is 1056 cm³