Question

a hollow cylindrical tube open at both ends is made of iron 3 cm thick. if the external diameter be 56 cm n the length of the tube be 182 cm, find the number of cubic cm in it.

Answer 1

Given, thickness of iron =3cm
          external diameter = 56cm
               Length of tube = 182cm
We know,
  volume of hollow cylinder = πh(R²−r²)
∴ internal diameter = external diameter−2×thickness of iron
                               = 56−2×3
                               = 56−6
                               = 50cm

=> Outer radius(R) = 56÷2 = 28cm
       inner radius(r) = 50÷2 = 25cm
∴ Volume of hollow cylinder = πh(R²−r²)
                                        = 3.14×182(28²−25²)
                                        = 3.14×82×159
                                        = 90865.32cm³       Answer

please see the attachment for diagram of cylinder mentioned in the question.

Answer 2

Answer:

hope it's help you

thank you