Question

A hollow hemispherical bowl is made of silver with its outer radius 8 cm and inner radius 4 cm respectively. the bowl is melted to form a solid right circular cone of radius 8 cm. the height of the cone formed is

Answer 1

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Answer 2

volume of the bigger hemisphere - volume of the smaller hemisphere = volume of the cone 

$\frac{2}{3} \pi ( R^{2} - r^{2} ) = \frac{2}{3} \pi R^{2} h$

64 - 16 = 64h

48/64 = h 

0.75cm = h