Question

A hollow metal pipe of inner diameter 6 cm and thickness 1 cm is melted and recast into a solid cylinder of the same length as that of the pipe. Find the area of cross-section of the solid cylinder. Please solve. 50 Points. ​

Answer 1

Answer:

p>Given, the height of the big cylinder (H) = 220 cmRadius of the base (R) = 24/12 = 12 cm

So, the volume of the big cylinder = πR2H

= π(12)2 × 220 cm3

= =99565.8 cm3

Now, the height of smaller cylinder (h) = 60 cm

Radius of the base (r) = 8 cm

So, the volume of the smaller cylinder = πr2h

= π(8)2 × 60 cm3

= 12068.5 cm3

∴ Volume of iron = Volume of the big cylinder + Volume of the small cylinder

99565.8 + 12068.5

=111634.5 cm3

We know,

Mass = Density x volume

So, mass of the pole = 8×111634.5

= 893 Kg (approx.)

Answer 2

Step-by-step explanation:

VINOD CHANGING SHAPE INTO ANOTHER SHAPE THEN THE VOLUME CANNOT BE CHANGED BY USING THIS WE CAN SOLVE THIS PROBLEM AND FIND THE AREA OF THE CROSS SECTION OF THE CYLINDER.

REFER TO THE ATTACHMENT