Question

A hollow metal surface of radius 5cm is cgarged such as that potential on its surface is 10v. What is potential at center of sphere

Answer 1

V=kQ/R^2[3/2R^2-1/2r^2]

So Initially r=R on surface

10=kQ/R^2[R^2]

10/k =Q

For Centre r=0

So

V=k ×10/k ×3/2

=15 V