Question

A hollow pipe has circumference 14 cm. a bug is on its wall (outside) at a distance of 48 cm from top. a drop of honey is on the wall (inside the pipe) at 24 cm from top but diametrically opposite to bug. find the shortest distance bug has to travel to reach honey.

Answer 1

total vertical distance 24 cm
circum.=14 cm
bug moves opposite then it covers half of cicum.
14/2=7cm

side²+side²=hypotenuse ²
√24²+7²=625 sq.feet
√625
25cm...!

Answer 2

Answer:

The shortest distance bug has to travel to reach honey is 25 cm

Step-by-step explanation:

Step 1:

Given Data:

Circumference of hollow pipe is 14 cm

Total vertical is 24 cm

Outside distance is 48 cm

Inside distance is 24 cm

To calculate the shortest distance:

Step 2:

The bug moves opposite then it covers half of circumference =

circumference /total vertices

14/2=7 cm

Step 3:

$\begin{array}{l}{\text { side }^{2}+\text { side }^{2}=\text { hypotenuse }^{2}} \\ {\sqrt{2} 4^{2}+7^{2}=625 \text { square } . \text { feet }} \\ {=\sqrt{625}} \\ {=25 \mathrm{cm}}\end{array}$