A hollow sphere is kept with a spin w gently on a rough horizontal floor .Find the fraction of total energy lost during sliding
Answers
Answered by
1
Explanation:
Let sphere of mass is M and radius is R.
Moment of inertia(MOI), I=
3
2
MR
2
Hollow sphere is rolling without slipping. ⇒v=Rω, Wherev is speed of centre of mass and ω is angular speed.
⇒ Translational KInetic Energy=
2
1
Mv
2
⇒ Rotational KInetic Energy=
2
1
Iω
2
=
2
1
×(
3
2
MR
2
)×(
R
v
)
2
=
3
1
Mv
2
⇒ Total Kinetic Energy=
2
1
Mv
2
+
3
1
Mv
2
=
6
5
Mv
2
⇒ % of Translational Energy=
6
5
Mv
2
2
1
Mv
2
×100=60%
Answered by
0
Answer:
Bernoulli's eqn =
Pressure at top = P°(atm.p)
pressure at bottom =( p°+ rho.g.h)
How did you cancel both ?
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