Math, asked by ssanjana9, 1 year ago

A hollow sphere of external and internal diameter 6cm and 4cm respectively is melted into a cone of base diameter 8cm.Find the height of the cone.

Answers

Answered by Anonymous
4

Answer:


Step-by-step explanation:

•If solid of one shape is converted into solid of another shape, then Total volume of the solid to be converted =  Total volume of the solid into which the given solid is to be converted.


SOLUTION :

Given : Internal diameter of hollow sphere(d)= 4 cm.

Internal radius of hollow sphere (r) = 4/2= 2 cm

external diameter of hollow sphere (D) = 6 cm.

external radius of hollow sphere( R )= 6/2= 3 cm.


Volume of the Hollow sphere = 4/3π(R³ - r³)

Volume of the Hollow sphere = 4/3π(3³ - 2³)

Volume of the Hollow sphere = 4/3π(27 - 8)

Volume of the Hollow sphere = 4/3π(19) cm³


Diameter of the cone(d1) = 8 cm

radius of the cone( r1)= 8/2 = 4 cm


Let the height of the cone be h cm.

Volume of the cone = ⅓ πr1²h

= ⅓ π × 4² × h = 16πh/3


Volume of the cone = Volume of the hollow sphere

16πh/3 = 4/3π(19)

16h = 4 ×19

h = (4 × 19)/16

h = 19/4 = 4.75cm


Hence, the height of the cone is 14 cm.


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Answered by sumisto
2

Step-by-step explanation:

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