A hollow sphere of external and internal diameter 6cm and 4cm respectively is melted into a cone of base diameter 8cm.Find the height of the cone.
Answers
Answer:
Step-by-step explanation:
•If solid of one shape is converted into solid of another shape, then Total volume of the solid to be converted = Total volume of the solid into which the given solid is to be converted.
SOLUTION :
Given : Internal diameter of hollow sphere(d)= 4 cm.
Internal radius of hollow sphere (r) = 4/2= 2 cm
external diameter of hollow sphere (D) = 6 cm.
external radius of hollow sphere( R )= 6/2= 3 cm.
Volume of the Hollow sphere = 4/3π(R³ - r³)
Volume of the Hollow sphere = 4/3π(3³ - 2³)
Volume of the Hollow sphere = 4/3π(27 - 8)
Volume of the Hollow sphere = 4/3π(19) cm³
Diameter of the cone(d1) = 8 cm
radius of the cone( r1)= 8/2 = 4 cm
Let the height of the cone be h cm.
Volume of the cone = ⅓ πr1²h
= ⅓ π × 4² × h = 16πh/3
Volume of the cone = Volume of the hollow sphere
16πh/3 = 4/3π(19)
16h = 4 ×19
h = (4 × 19)/16
h = 19/4 = 4.75cm
Hence, the height of the cone is 14 cm.
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