A hollow sphere of inner and outer diameter of 12 cm and 16 cm respectively floats half submerged in water. Calculate specific gravity
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Answer:
The answer is 0.865
Explanation:
For equilibrium, the weight of sphere must balance buoyancy force.
Volume= 4/3π(8^3*10^-6 - 6^3*10^-6)
=4/3π296 *10^-6
Fb=Fw
4/3π512*10^-6(rho of air)g
=4/3π296*10^-6(rho of material)g
ρ air/ρmateria
= 2×296/512
=0.865
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