Question

A hollow spherical ball of thickness lcm and external radius 5c
obtained, without any loss of material 61 identical spherical bal
of each ball?
O1
2,631161
O 1.5
313163116
O 3
02​

Answer 1

ʜᴇʀᴇ ɪs ʏᴏᴜʀ ᴀɴsᴡᴇʀ. ...❤

ʀᴇsɪsᴛᴀɴᴄᴇ ɪs ᴀ ᴍᴇᴀsᴜʀᴇ ᴏғ ᴛʜᴇ ᴏᴘᴘᴏsɪᴛɪᴏɴ ᴛᴏ ᴄᴜʀʀᴇɴᴛ ғʟᴏᴡ ɪɴ ᴀɴ ᴇʟᴇᴄᴛʀɪᴄᴀʟ ᴄɪʀᴄᴜɪᴛ. ʀᴇsɪsᴛᴀɴᴄᴇ ɪs ᴍᴇᴀsᴜʀᴇᴅ ɪɴ ᴏʜᴍs, sʏᴍʙᴏʟɪᴢᴇᴅ ʙʏ ᴛʜᴇ ɢʀᴇᴇᴋ ʟᴇᴛᴛᴇʀ ᴏᴍᴇɢᴀ (ω). ᴏʜᴍs ᴀʀᴇ ɴᴀᴍᴇᴅ ᴀғᴛᴇʀ ɢᴇᴏʀɢ sɪᴍᴏɴ ᴏʜᴍ (1784-1854), ᴀ ɢᴇʀᴍᴀɴ ᴘʜʏsɪᴄɪsᴛ ᴡʜᴏ sᴛᴜᴅɪᴇᴅ ᴛʜᴇ ʀᴇʟᴀᴛɪᴏɴsʜɪᴘ ʙᴇᴛᴡᴇᴇɴ ᴠᴏʟᴛᴀɢᴇ, ᴄᴜʀʀᴇɴᴛ ᴀɴᴅ ʀᴇsɪsᴛᴀɴᴄᴇ.

ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘs...

ᴘʟᴇᴀsᴇ ᴍᴀʀᴋ ʙʀᴀɴɪʟᴇsᴛ ᴀɴsᴡᴇʀ...❤

Answer 2

Answer:

ANSWER

The density of material is is ρ

The hollow sphere will float if its weight is less than the weight of the water displaced by the volume of the sphere This implies mass of the sphere is less than that for the same volume of water. Now, mass of spherical cell

m

1

=4πR

2

×t×ρ

While the mass of water having same volume

m

2

=

3

4

πR

3

×ρ

g

=

3

4

πR

3

where, ρ

g

= density of water 1 g.cm

−3

For the floatation of sphere,

m

1

≤m

2

4πR

2

×t×ρ≤

3

4

πR

3

⇒tρ≤

3

R

⇒t≤

3ρ

R