Question

a hollow spherical iron shell has an internal radius of 3 cm and external radius of 6cm. how much iron is there in there in the shell? with solution plz friends with whole solution plz​

Answer 1

Answer:

Internal radius = r = 3 cm

external radius = R = 6 cm

Volume of Iron = Volume of External Sphere Shell - Volume of Internal Sphere

$= \frac{4}{3} \pi {R}^{3} - \frac{4}{3} \pi {r}^{3} \\ = \frac{4}{3} \pi( {R}^{3} - {r}^{3} ) \ \ \\ = \frac{4}{3} \times \frac{22}{7} ( {6}^{3} - {3}^{3} ) \\ = \frac{4}{3} \times \frac{22}{7} (216 - 27) \\ = \frac{4}{3} \times \frac{22}{7} \times 189 \\ = \frac{4 \times 22 \times 27}{3} \\ = 88 \times 9 \\ = 792 \: {cm}^{3}$