a hollow spherical shell carries charge density in the region a<=r<=b.Find the electric field in three regions (i)r<a,(ii)a<r<b,(iii)r>b
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Answer:
i. 0 N/C ii.kq/r^2 N/C iii.0 N/C
Explanation:
When r<a, there is no charge density in the hollow sphere as r>=a(given). Therefore electric field is 0.
When r lies between a and b electric field acrs hue to the presence of the surface charge which can be calculated by the formula E= kq/r^2 where k=1/4 pi € and q=surface charge density.
When r>b, again there is no charge density in a similar way as in case of (i). thus E=0.
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