A hollow spherical shell is made of a metal of density 4.5/cm^3. if its internal and external diameters are 8cm and 9cm respectively, find the wieght of the shell
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Answer:
Step-by-step explanation:
External diameter = 9 cm
External radius = 4.5 cm
Internal diameter = 8 cm
Internal radius = 4 cm
Volume of hollow spherical shell = 4/3×π(R²-r²)
= 4/3×3.14[(4.5)²-(4)²]
= 4/3×3.14[20.25-16]
= 4/3(3.14)(4.25)
= 4/3(13.35)
= 53.4/3
= 17.8 cm³
Density of metal = 4.5 g/cm³
Density = Mass/Volume
Mass of metal = Density×Volume
= 4.5 × 17.8
= 80.1 g
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