A hollow spherical shell is made of a metal of density 4.5g per cm cube .If its internal and external radii are 8 cm and 9 cm respectively find the weight of the shell
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let r and R be the internal and external radii of hollow spherical shell.
since , internal radius of the shell = 8cm
external radius of the shell = 9 cm
Find the volume of the shell:
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volume of the shell = 4/3 πR^3 - 4/3πr^3
= 4/ 3 π( R^3 - r^3 )
= 4 /3 π [ (9)^3 - (8)^3 ]
= 4 / 3 π ( 729 - 512 )
= (4 /3) π × 217 = (4/3 )× 217 × (22/ 7)
= 2728 / 3 cm^3
Given , weight of 1cm^3 = 4.5g ,then
Find the weight of the shell:
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weight of the shell
= (2728/ 3) × 4.5 = 4092 g
therefore, weight of the spherical shell
= 4092 g
Answer : weight = 4092 g
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since , internal radius of the shell = 8cm
external radius of the shell = 9 cm
Find the volume of the shell:
---------------------------------------
volume of the shell = 4/3 πR^3 - 4/3πr^3
= 4/ 3 π( R^3 - r^3 )
= 4 /3 π [ (9)^3 - (8)^3 ]
= 4 / 3 π ( 729 - 512 )
= (4 /3) π × 217 = (4/3 )× 217 × (22/ 7)
= 2728 / 3 cm^3
Given , weight of 1cm^3 = 4.5g ,then
Find the weight of the shell:
--------------------------------------
weight of the shell
= (2728/ 3) × 4.5 = 4092 g
therefore, weight of the spherical shell
= 4092 g
Answer : weight = 4092 g
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