Question

A hollow spherical shell is made of a metal of density 9.6g / cm3 .

The external diameter of the shell is 10cm and its internal diameter is 9cm . Find( i ) Volume of the metal contained in the shell

( ii) Weight of the shell ( iii ) Outer surface area of the shell.

Answer 1

Answer:

Step-by-step explanation:

Since a hollow spherical shell is made of a metal of density 9.6 g/cm3. The external diameter of the shell is 10 cm and its internal diameter is 9 cm, our aim is to:

1. Volume of the metal contained in the shell;
2. Weight of the shell;
3. Outer surface area of the shell.

Hence, let R = 10 cm be the external diameter and r = 9 cm be the internal diameter.

Therefore, the volume is equal to:

$\frac{4}{3} pi(R^{3} -r^{3}) = \frac{4}{3} *\frac{22}{7} *(10^{3} -9^{3})\\ V = \frac{88}{21} *(1000-729) = \frac{88}{21} * 271 = 1135.62 cm^{3}$

Since 1 centimeter cubic is equal to 4.5 gm, we conclude that the weight of the spherical shell is equal to 1135.62 * 4.5 = 5.110 kg