Question

A hollow square shaped tube open at both ends is made of iron. The internal square is of 5m side and the lenght of the tube is 2m. There are 192cm^3 of iron in this tube. Find it's thickness​

Answer 1

Answer:

Cross-sectional area of iron tube = 192 cm³ / 8 cm = 24 cm²

A = s² - 5² = 24 cm²

s² = 25 + 24 = 49 cm²

s = √(49 cm²) = 7 cm

thickness = ½(7 - 5) = 1 cm

Answer 2

Answer:

The thickness of the tube will be 1 cm.