A hollow squared shaped tube open at both ends is made up of iron. Threw internal square is of 5cm side and the length of the tube is 8 cm. There are 192 cm^3 of iron in this tube. Find it's thickness.
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Cross-sectional area of iron tube = 192 cm³ / 8 cm = 24 cm²
A = s² - 5² = 24 cm²
s² = 25 + 24 = 49 cm²
s = √(49 cm²) = 7 cm
thickness = ½(7 - 5) = 1 cm
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