Question

A hollow uniformly charged sphere has radius r. If the potential difference between its surface and a



point at distance 3r from the centre is v, then the electric field intensity at a distance 3r from the



centre is?

Answer 1

potential at the surface of hollow sphere , V = kq/r , where q is charge distributed on the surface of hollow sphere.

a/c to question,

potential at the surface - potential at 3r distance from teh centre = v

or, kq/r - kq/3r = v

or, 2kq/3r = v

or, q = 3rv/2k .....(1)

now electric field intensity at a distance 3r from the centre is E = kq/(3r)²

from equation (1),

E = k(3rv/2k)/9r²

= 3rv/18r²

= v/6r

hence, answer is v/6r

Answer 2

Answer:

v/6r

Explanation:

potential at the surface of hollow sphere , V = k/r , where q is charge distributed on the surface of hollow sphere.

a/c to question,

potential at the surface - potential at 3r distance from teh centre = v

or, k/r - k/3r = v

or, 2kq/3r = v

or, q = 3rv/2k ..(1)

now electric field intensity at a distance 3r from the  is E = k/(3r)²

from equation (1),

E = k(3rv/2k)/9r²

= 3rv/18r²

= v/6r

hence, answer is v/6r