A Honda fits accelerate from 0 to 60mph(27ms)in 9.5 sec. What is it's accelertaion?
supposed that the breaks are applied and it slows from 27ms to 18 ms while 45 m. what constant deceleration did it have?
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Answer:
V^2=u^2 + 2*a*s
V is final velocity.
u is initial velocity.
a is acceleration.
s is distance.
27^2=9^2+ 2 ((27–9)/5) s
729=81 + 2 (7.2) s
648=7.2 s
90 m =s
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