Question

A honey bee flies in circles around a flower. If the velocity of the bee is 670 cm/s and the radius of the circular path is 2.0 cm, what is the centripetal acceleration of the honey bee?

Answer 1

Answer:

224450 cm/s^2

Explanation:

cent force = (mv^2)/r

f =ma.    a=f/a

cent acceln =v^2/r

Answer 2

Answer:

Centripetal acceleration of the honey bee, $a=2244.5\ m/s^2$

Explanation:

Given that,

Velocity of the bee, v = 670 cm/s = 6.7 m/s

Radius of the circular path, r = 2 cm = 0.02 m

Let a is the centripetal acceleration of the honey bee. Its expression is given by :

$a=\dfrac{v^2}{r}$

$a=\dfrac{(6.7)^2}{0.02}$

$a=2244.5\ m/s^2$

So, the centripetal acceleration of the honey bee is $2244.5\ m/s^2$

Learn more :

Topic : Uniform circular motion

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