Question

A hoop and disc have same mass and radius. Their rotational k.e is related by an equation
a. K.Ehoop=K.Edisc
b.K.Ehoop=2K.Edisc
c.K.Ehoop=1/2K.Edisc
d.K.Ehoop=4K.Edisc​

Answer 1

Answer:

A hoop and disc have same mass and radius. Their rotational k.e is related by an equation

a. K.Ehoop=K.Edisc

b.K.Ehoop=2K.Edisc

c.K.Ehoop=1/2K.Edisc

d.K.Ehoop=4K.Edisc

l don't know

Answer 2

Answer:

The rotational kinetic energy in each case is [math] K =\frac{1}{2} I \omega^2[/math] where I is the moment of inertia and [math]\omega [/math] is the angular velocity. The distribution of mass in a hoop and a disk are different so the moments of inertia are different. A hoop of mass m and radius r has a moment of inertia[math] I=mr^2[/math] whereas a disk of radius r and mass m has a moment of inertia of [math]I=\frac{1}{2} mr^2[/math] about the axis perpendicular to the plane of the disk (see ). In general moment of inertia is a tensor quantity and its value is dependent upon the orientation of the axis wrt the symmetry of the object

Explanation:

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