Physics, asked by chebrolumahi83, 11 months ago

A hoop of mass M and radius R is ssuspended on a peg in a wall. Its moment of inertia about the peg is

Answers

Answered by Prakarsh01

Explanation:

The moment of inertia of hoop about axis passing from its center and perpendicular to its plane is Mr2, so using parallel axis theorm, MI about peg in its plane is Mr2+M(r)2=2Mr2.

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