Question

A hoop with moment of inertia I = 0.1 kgm2 spins about a frictionless axle with an angular velocity of 5 rads/s. At what radius from the center of the hoop should a force of 2N be applied for 3s in order to accelerate the hoop to an angular speed of 10 rads/s?

Answer 1

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Answer 2

Answer: 8.3cm

Explanation: You can use the equation for vector(acceleration)=net torque over rotational inertia, 0.1/2((10-5)/3) and you’ll get 0.083, then convert to cm