Question

A horizontal circular disc having a mass of 120 kg and radius of gyration of 430 mm is fixed ti the bottom end of a vertical circular shaft whose axis is passing through center of axis the upper end of the shaft is fixed to the roof. The length of the shaft is 1.2m dia 45mm

Answer 1

Explanation:

Answer:300 rad /s

Explanation:use the relation I* angular acceleration = torque .

Get angular acceleration and using that substitute in omega= initial angular velocity + alpha *time ....you will get omega that is angular velocity

Answer 2

Answer:

A horizontal circular disc having a mass of 120 kg and radius of gyration of 430 mm is fixed ti the bottom end of a vertical circular shaft whose axis is passing through center of axis the upper end of the shaft is fixed to the roof. The length of the shaft is 1.2m dia 45mm