Math, asked by rohith2244, 6 months ago

A horizontal conveyor belt moves with a constant velocity

V. A small block is projected with a velocity of 6 m/s on it in a direction opposite to the direction of motion of the belt. The block comes to rest relative to the belt in a time 4s. = 0.3, g = 10 m/s. Find V.

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Answered by Sumudawe

Answer:

A horizontal conveyor belt moves with a constant velocity V. A small block is projected with a velocity of 6m/s on it in a direction opposite to the direction of motion of the belt The block comes to rest relative to the belt in a time 4s. μ=0.3,g=10.

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