Question

A horizontal force 10 Newton is necessary to just hold a block stationary against a wall. the coefficient of friction between the block and the wall is 0.2, the weight of the block is

Answer 1

Answer:

Friction force balance the wight of the block

friction force f=μN=0.2×10=2N

2N must be the wight of the block so that it is in equilibrium

Hence the correct option is C.

Explanation:

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Answer 2

ANSWER :-

2N (or) 2 newton

SOLUTION:-

NOTE :-

• Here, friction balances the weight in vertical direction , hence we may equate friction to weight of the block
• Friction = u $N_r$
• Here ,
• Given ,$N_r=10N$
• u = Coeeficient of friction = 0.2

Now, equating weight to friction ,

Weight = u $N_r$

Weight = 0.2 × 10

Weight = 2N

Therefore weight of the block = 2N