A horizontal force is applied on a plank. The acceleration of the plank is a = (4t) m/s2 for. after the end of acceleration , the plank continues to move at a constant speed. the block initially at rest on the plank begins to slip at t=1s and stops slipping at t =3s . Find the ratio of coefficient of Static friction and kinetic friction between block and plank
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Answered by
1
Explanation:
Answer
7
Solution
μsg=dvdt at t=1 sec
∴μs=0.4
At t=3 sec velocities of plank and block are equal.
∴2+μkg(2)=v at t=3 sec =8
∴μk=0.3
∴s+k=4+3=7
Answered by
0
Answer:
7
Explanation:
μsg=dvdt at t=1 sec
∴μs=0.4
At t=3 sec velocities of plank and block are equal.
∴2+μkg(2)=v at t=3 sec =8
∴μk=0.3
∴s+k=4+3=7
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