Question

A horizontal force of 1.2 kg is applied on a 1.5 kg block, which rests on a horizontal surface. If the coefficient of friction is 0.3, find the acceleration produced in the block.

Answer 1

we know

Fsmax = N×μs

1.2 = 0.3×(1.5×a)

1.2 = 0.45a

12=4.5 ×a

a = 120/45

a = 2.67 m/s^2