Question

A horizontal force of 10 N acts on a body of mass 1 kg at rest.

The work done by the body in 4 seconds is

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Answer 1

Explanation:

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Answer 2

Answer:

800J

Explanation:

U=0m/s

F=ma

a=F÷m

So,a=10÷1=10

S=ut+1/2 at×t

=1/2 ×10×16

=80

W=FS

10×80

=800J

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