a horizontal force of 12 N is applied to a 1500g block which rests on a horizontal surface. if the coefficient is 0.3. find the acceleration produced in the block
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DUDE IT IS A SIMPLE QUESTION OF FRICTION ...
GIVEN,
F = 12 N
MASS = 1500 g = 1.5 Kg
coefficient of friction ( U) = 0.3
F= MaU
a = F/ M U
= 12/ 1.5 × 0.3
= 26.6667.m/s^2 ...... (ANS)
@AMINUL. HOQUE.
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