Question

A horizontal force of 1200 gf is applied to a 1200 g block , which rest on a horizontal surface. If the coefficient of friction is 0•2, find the acceleration produced in the block .​

Answer 1

Answer:

Horizontal force

F=1.2kgwt

F

1

=1.2×g

Now frictional force

F=umg

F=0.3×1.5×g

F=0.45g

Let acceleration produced in the body be a.

Now we have

F

1

−F=ma

1.2g−0.45g=1.5a

0.75g=1.5a

a=

2

g

a=4.9m/s

2

Explanation:

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