a horizontal force of 200 newton is required to slide A 15 kg block upto 20 degree incline with an acceleration of 25 cm per second square the coefficient of friction between the block and the inclined surfaces will be? (sin 20 degrees equal .34 cos 20 degree equal .94)
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Answer:
0.25
Explanation:
Given,
a=25m/sec^2
mass=15 kg
we know that when a block slides up with velocity u then it retards with acceleration 'a' .
friction=mu mgcostheta
a=g sintheta + mu gcostheta
on putting the values in given equation we get,
mu= 0.25
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