Question

A horizontal force of 32 N acts on a body of mass 3 kg. Find the acceleration of the body if no other force acts on it.

Answer 1

Given:

• Force (F) = 32 N
• Mass of the body (m) = 3 kg

To find:

• Acceleration of the body (a) = ?

Solution:

♧ F = m × a ♧

(putting values)...

==> 32 = 3 × a

==> 32/3 = a

==> 10.67 m/s^2 = a

Hence, the acceleration of body = 10.67 m/s^2

Hope it helped you dear...

Answer 2

Given :

• Mass of the body = 3 kg

• Horizontal force = 32 N

To find :

The acceleration produced by the body.

Solution :

We know that :

• The force is directly proportional to the mass of the body .i.e, If the mass of the body will be more , force applied will also be greater.

$\bf{F \propto m}$⠀⠀⠀⠀⠀Eq.(i)

Where :

 ⠀⠀⠀⠀⠀⠀⠀⠀F = Force

⠀⠀⠀⠀⠀⠀⠀⠀m = Mass

• The force is directly proportional to the acceleration of the body .i.e, If the mass of the body will be more , force applied will also be greater.

$\bf{F \propto a}$⠀⠀⠀⠀⠀Eq.(ii)

Where :

⠀⠀⠀⠀⠀⠀⠀F = Force

⠀⠀⠀⠀⠀⠀⠀a = Acceleration

putting the two Equations together , we get :

$:\implies \bf{F \propto ma}$

Or

$:\implies \bf{F = k\:ma}$

Here , Constant (k) is equal to 1.

Hence, the formula for force is :

$\boxed{\therefore \bf{F = ma}}$

Now using the equation for Force and Substituting the values in it , we get :

$:\implies \bf{F = ma}$

$:\implies \bf{32 = 3 \times a}$

$:\implies \bf{10.67 = a}$

$\boxed{\therefore \bf{a = 10.67\:ms^{-2}}}$

Hence the acceleration produced by the body is 10.67 m/s².