Question

a horizontal force of 5 N is required to maintain a velocity of 2 m/s for a block of 10 kg mass sliding over a rough surface. The work done by this force in one minute is

Answer 1

$\huge\underline\purple{\sf Answer:-}$

★$\large{\boxed{\sf Worke\:Done(W)=600J}}$

$\huge\underline\purple{\sf Solution:-}$

★Given :-

Velocity (v) = $\sf{2m/s}$

Mass (m) = 10 lg

Force (F) = 5N

Time (t) = 1 min => 60 seconds

★$\large{\boxed{\sf Work=Force×Displacement}}$

$\large\implies{\sf F×(V×t)}$

$\large\implies{\sf 5×(2×60)}$

$\large\implies{\sf 600 J}$

★$\large\red{\boxed{\sf Work\:Done=600J}}$

Answer 2

$\huge{\mathfrak{\underline{\pink{Answer:-}}}}$

$\large\orange{\boxed{\bf Work \: done=600J ...}}$

$\large\star\bf{\bold{\underline{\underline{Given:-}}}}$

•$\large\sf\ Velocity(v)=2m/s$

•$\large\sf\ Mass(m)=2kg$

•$\large\sf\ Force(f)=5N$

•$\large\sf\ Time(t)=1minute =60seconds$

$\large\star\bf{\bold{\underline{\underline{To \: find :-}}}}$

•$\large\sf\ Work \: done (w)= ?$

$\large\star\bf{\bold{\underline{\underline{Solution:-}}}}$

We know that ;

$\large\bf\ Work=Force \times\ Displacement$

So consitute the given values in formula ;

$\large\sf\ W= f \times\ s \\ \\ \large\sf\implies\ f \times\ (v \times\ t) \\ \\ \large\sf\implies\ 5 \times\ (2 \times\ 60) \\ \\ \large\bf\implies\ 600J$