Question

A horizontal force of 50 N displaces an object of mass 100 kg.Calculte the distance moved and worked done by the force in 8 second.​

Answer 1

SOLUTION

GIVEN

A horizontal force of 50 N displaces an object of mass 100 kg.

TO CALCULATE

The distance moved and worked done by the force in 8 second.

EVALUATION

Here by the given -

Force = F = 50 N

Mass = m = 100 kg

Let acceleration = a

We know that

F = ma

⇒ 50 = 100a

∴ a = 0.5

Thus Acceleration = 0.5 m/s²

Now the distance moved

$\displaystyle \sf{ = \frac{1}{2}a {t}^{2} \: \: metre }$

$\displaystyle \sf{ = \frac{1}{2} \times 0.5 \times {8}^{2} \: \: metre }$

$\displaystyle \sf{ = \frac{1}{2} \times 0.5 \times 64 \: \: metre }$

$\displaystyle \sf{ =16\: \: metre }$

Now work done

= F × d

= 50 × 16 Joule

= 800 Joule

FINAL ANSWER

The distance moved = 16 metre

The worked done = 800 Joule

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Answer 2

Answer:800 J and 16m

Explanation:

GIVEN

A horizontal force of 50 N displaces an object of mass 100 kg.

TO CALCULATE

The distance moved and worked done by the force in 8 second.

EVALUATION

Here by the given -

Force = F = 50 N

Mass = m = 100 kg

Let acceleration = a

We know that

F = ma

⇒ 50 = 100a

∴ a = 0.5

Thus Acceleration = 0.5 m/s²

Now the distance moved

Now work done

= F × d

= 50 × 16 Joule

= 800 Joule

FINAL ANSWER

The distance moved = 16 metre

The worked done = 800 Joule