a horizontal force of 500N pulls two masses, 10 kg and 20 kg. What is the tension in the string - a. When the force is applied on the right side on 20 kg mass. b. When the force is applied on the left side on 10 kg mass.
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If a is the acceleration of the system,
F = (10 + 20)a = 500N
a = 50/3 m/s²
a. Force applied on 20kg mass.
T = 10a = (10×50)/3 = 500/3 N
b. Force applied on 10kg mass.
T = 20a = (20×50)/3 = 1000/3 N
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