A horizontal force of 5N act on a block of mass 10 kg kept
on a rough horizontal surface. The coefficient of friction
between the block and the rough surface is 0.3. Find the
magnitude of frictional force acting between them, (g = 10
m/s2)
Answers
Answered by
5
N=mg
N=10×10
=100
fr=0.3×100
=30 N
N=10×10
=100
fr=0.3×100
=30 N
Answered by
1
Answer:
5 N
Explanation:
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