Physics, asked by muniba45, 1 year ago

A horizontal force of 5N is required to maintain a velocity of 2m/s for a block
10kg mass sliding over a rough horizontal surface. The work done by this for
in one minute is :
(A) 600J
(B)60J
(C)6J
(D)6000J
reply plz​

Answers

Answered by iamalover
41

Here is the answer mate...

Attachments:
Answered by muscardinus
13

Answer:

Work done, W = 600 J

Explanation:

It is given that,

Force acting on the block, F = 5 N

Velocity of the block, v = 2 m/s

Mass of the block, m = 10 kg

Time force which the force is applied, t = 1 min = 60 sec

The product of the force and the displacement is called work done by the force. It is given by :

W=F\times d

W=F\times (v\times t)

W=5\ N\times (2\ m/s\times 60\ s)

W = 600 Joules

So, the work done by this for  in one minute is 600 Joules. Hence, this is the required solution.

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