A horizontal force of the 500 Newton pulls two masses 10 kg and 20 kg connected with a light string when placed on frictionless horizontal table the tension in the string if force is applied on 10 kg mass is
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Answer:
Tension on string=force applied on 10 kg mass.
30(20+10)kg required 500 Newton.
10 kg required 500/3
=166.7 N
Explanation:
Answered by
0
AnswerTension on string=force applied on 10 kg mass.
30(20+10)kg required 500 Newton.
10 kg required 500/3
=166.7 N
:
Explanation:
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